dgarcia4895 dgarcia4895
  • 19-07-2022
  • Mathematics
contestada

factorizacion de x^4+12x^3-64x^2=0

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skabetix skabetix
  • 19-07-2022

Hello,

x⁴ + 12x³ - 64x² = 0

x²(x² + 12x - 64) = 0

x² = 0 or x² + 12x - 64 = 0

x = 0

∆ = b² - 4ac = 12² - 4 × 1 × (-64) = 400

x1 = (-b -√∆)/2a = (-12 - 20)/2 = -32/2 = -16

x2 = (-b + √∆)/2a = (-12 + 20)/2 = 8/2 = 4

S = {-16 ; 0 ; 4 }

→ factorizacion de x⁴ + 12x³ - 64x² : x(x - 4)(x + 16)

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