DavidCopperfield
DavidCopperfield DavidCopperfield
  • 18-07-2022
  • Mathematics
contestada

Can any one help me?​

Can any one help me class=

Respuesta :

dondaviesmckings dondaviesmckings
  • 18-07-2022

Answer:

64

Step-by-step explanation:

2x-4y=3

x= (3 +4y)/2

substitute into the main equation

y= 0

x= 3/2

16^x /256^y

16^3/2 ÷ 256^0

√16^3 ÷1

= 64

Answer Link
mathstudent55
mathstudent55 mathstudent55
  • 18-07-2022

Answer:

64

Step-by-step explanation:

2x - 4y = 3

2x = 4y + 3

x = 2y + 1.5

[tex] \dfrac{16^x}{256^y} = [/tex]

[tex] = \dfrac{16^{2y + 1.5}}{256^y} [/tex]

[tex] = \dfrac{16^{2y + 1.5}}{16^{2y}} [/tex]

[tex] = 16^{2y + 1.5 - 2y} [/tex]

[tex] = 16^\frac{3}{2} [/tex]

[tex] = 4^3 [/tex]

[tex] = 64 [/tex]

Answer Link

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