symartinez20 symartinez20
  • 16-07-2022
  • Mathematics
contestada

Given sin a=−2/5 and cos b=1/3 with a and b both in the interval (3π/2,2π), find sin(a+b)

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evgeniylevi
evgeniylevi evgeniylevi
  • 16-07-2022

Answer:

[tex]-\frac{8\sqrt{2}+2}{15}.[/tex]

Step-by-step explanation:

1) sin(a+b)=sin(a)cos(b)+sin(b)cos(a);

2) if sin(a)=-0.4, then cos(a)=0.8; if cos(b)=1/3, then sin(b)=-√8/3;

3) finally, sin(a+b)=-0.4*1/3-√8/3*0.8=

[tex]=-\frac{8\sqrt{2}+2}{15}.[/tex]

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