Answer:
x=5
Step-by-step explanation:
[tex]((x+3)/4)+(((2x-12)-1)/3)=1\\\frac{x+3}{4} +\frac{2x-12-1}{3} =1\\\frac{x+3}{4} +\frac{2x-13}{3} =1\\[/tex]
Now we have to cross multiply the denominator to progress further.
[tex]\frac{3(x+3)}{4*3} +\frac{4(2x-13)}{3*4} =1\\\frac{3x+9}{12} +\frac{8x-52}{12} =1\\\frac{3x+9+(8x-52)}{12} =1\\\frac{3x+9+8x-52}{12} =1\\\frac{11x-43}{12} =1\\11x-43=12\\11x=43+12\\11x=55\\x=\frac{55}{11} \\=5[/tex]
