Answer:
first function:
[tex] f(x) = \dfrac{2 - 10}{2 - 0} x + 10 = \\ - 4x + 10[/tex]
second one:
[tex]g(x) = \cfrac{ - 4 - 2}{2 - 0} x + 2 = \\ - 3x + 2[/tex]
now the intersection:
-4x+10=-3x+2
x=8
then y
y = -4×8+10 = -22
so it's
(8,-22)
