Answer:
8.32
Step-by-step explanation:
We can find the perimeter by summing up the lengths AB,BC and AC
Now let's find the individual lengths aforementioned.
|AB|=√(3-3)²+(2-4)²
=√4
|AB|=2
|BC|=√(3-6)²+(4-3)²
=√9+1
|BC|=3.16
|AC|=√(3-6)²+(2-3)²
=√9+1
|AC|=3.16
Now the individual lengths have been found so perimeter=2+3.16+3.16=8.32(to two decimal places)
