23mking
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I need help on this!
Given the following right triangle △ ABC with m∠A = Θ°, find sin(Θ°) and cos(Θ°).

I need help on this Given the following right triangle ABC with mA Θ find sinΘ and cosΘ class=

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devishri1977

Answer:

[tex]\sf Sin \ \theta = \dfrac{5}{13}\\\\Cos \ \theta =\dfrac{12}{13}[/tex]

Step-by-step explanation:

  [tex]\sf Sin \ \theta= \dfrac{opposite \ of \ angle \ A}{hypotenuse}\\\\[/tex]

            [tex]\sf =\dfrac{BC}{AB}\\\\ =\dfrac{5}{13}[/tex]

[tex]\sf Cos \ \theta = \dfrac{adjacent \ side \ of \ angle \ A}{hypotenuse}\\[/tex]

       [tex]\sf =\dfrac{AC}{AB}\\\\= \dfrac{12}{13}[/tex]

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