kayla729 kayla729
  • 20-04-2022
  • Chemistry
contestada


10 grams CH10 + excess O2 → ? grams CO2 + H2O

Respuesta :

jsimpson11000 jsimpson11000
  • 22-04-2022

Answer:

20  gm  CO2

Explanation:

CH10   mole weight = ~ 22 gm

  each 22 gm CH10 produces 44 gm CO2

        44 / 22 = x / 10 = 20 gm

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