Answer:
[tex]y = 0.835193[/tex] (use the '≈' )
Step-by-step explanation:
[tex]y^3+2y^2+12y+16=28[/tex] (original equation)
[tex]y^3+2y^2+12y+16 - 28 =28 -28[/tex] (subtract 28 from both sides)
[tex]y^3+2y^2+12y-12=0[/tex] (new equation)
then use the cubic formula (i don't really know how to explain the process through a screen. I'm sorry! Hopefully, this helps enough though)
