Check the picture below.
[tex]\textit{volume of a pyramid}\\\\ V=\cfrac{Bh}{3}~~ \begin{cases} B=\stackrel{base}{area}\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{149\times 149}{22201}\\ h=91 \end{cases}\implies V=\cfrac{(22201)(91)}{3}\implies V=673430.\overline{3}~m^3[/tex]
