jessicabrewaah
jessicabrewaah jessicabrewaah
  • 21-03-2022
  • Mathematics
contestada

Find the equation of a line that passes through the point (1,-4) and has a gradient of -3. Leave your answer in the form y=mx+c​

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aliciat8924
aliciat8924 aliciat8924
  • 21-03-2022
Answer: y=-3x-1

Explanation: Sub the coordinates into y=mx+c to find c
-4=-3x1+c
-4=-3+c
c=-1

Then just re write it in y=mx+c to get y=-3x-1
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jdoe0001 jdoe0001
  • 21-03-2022

[tex](\stackrel{x_1}{1}~,~\stackrel{y_1}{-4})\qquad \qquad \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{-3}(x-\stackrel{x_1}{1}) \\\\\\ y+4=-3x+3\implies y=-3x-1[/tex]

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