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  • 20-03-2022
  • Mathematics
contestada

For what value of p are 2p + 1, 13, 5p – 3, three consecutive terms of AP?​

Respuesta :

algebraic12 algebraic12
  • 20-03-2022

Answer:

4

Step-by-step explanation:

The arithmetic progression terms, are

(2p+1), 13, (5p-3).

First find the distance between 2p+1 and 13.

[tex]13 -( 2p + 1 )= - 2p + 12[/tex]

Then find distance between 13, and 5p-3

[tex]5p - 3 - ( 13) = 5p - 16[/tex]

Terms in a AP progression should have same distances as each other.

[tex]5p - 16 = - 2p + 12[/tex]

[tex]7p = 28[/tex]

[tex]p = 4[/tex]

Answer Link
Аноним Аноним
  • 20-03-2022

Answer:

Given 2p+1, 13 , 5p-3 are in AP. P is 4.

Answer Link

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