23morrissettea
23morrissettea 23morrissettea
  • 18-03-2022
  • Mathematics
contestada

[tex]6+\sqrt[5]{249-2x} =7[/tex]

Respuesta :

GeorgePP
GeorgePP GeorgePP
  • 18-03-2022

Answer: 124

Step-by-step explanation:

First, subtract 6 on both sides to get:

[tex]\sqrt[5]{249-2x} =1[/tex]

Take both sides to the 5th power. The radical will cancel, and the right side will be unchanged:

[tex]249-2x=1[/tex]

Subtract 249 on both sides:

[tex]-2x=-248[/tex]

[tex]2x=248[/tex]

[tex]x=124[/tex]

Answer Link
surjithayer surjithayer
  • 18-03-2022

Answer:

x=124

Step-by-step explanation:

[tex]6+\sqrt[5]{249-2x} =7\\\sqrt[5]{249-2x} =7-6=1\\249-2x=1^5=1\\249-1=2x\\2x=248\\x=\frac{248}{2} =124[/tex]

Answer Link

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