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A sample of oxygen gas is collected over water.
The volume of gas collected is 0.250 L at 26°C and
765 torr total pressure. (Water vapor pressure at 26°C = 25.22 torr)

How many grams of oxygen gas are collected?

Respuesta :

Eduard22sly

The mass of the oxygen gas collected over water is 0.317 g

How to determine the mole of oxygen  

  • Volume (V) = 0.250 L
  • Temperature (T) = 26 ˚C = 26 + 273 = 299 K
  • Pressure (P) = 765 – 25.22 = 739.78 torr = 739.78 / 760 = 0.973 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

The number of mole can be obtained as by using the ideal gas equation as illustrated below:

n = PV / RT

n = (0.973 × 0.25) / (0.0821 × 299)

n = 0.0099 mole

How to determine the mass of oxygen collected

  • Mole of oxygen = 0.0099 mole
  • Molar mass of oxygen = 32 g/mol
  • Mass of oxygen =?

Mass = mole × molar mass

Mass of oxygen = 0.0099 × 32

Mass of oxygen = 0.317 g

Learn more about ideal gas equation:

https://brainly.com/question/4147359

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