tthe61443 tthe61443

19-02-2022
Mathematics

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find all values of x for which the perimeter is at most 32

find all values of x for which the perimeter is at most 32 class=

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semsee45 semsee45

19-02-2022

Answer:

0 < x ≤ 11

Step-by-step explanation:

perimeter = (x - 6) + (x - 6) + x + x

⇒ perimeter = 4x - 12

If the perimeter is "at most 32" then

4x - 12 ≤ 32

⇒ 4x ≤ 44

⇒ x ≤ 11

Therefore, 0 < x ≤ 11

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