[tex]\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2[/tex]
Moles of copper nitrate:-
[tex]\\ \tt\hookrightarrow \dfrac{1.876}{187.56}=0.001mol[/tex]
- 1mol of Copper nitrate reacts with 2mol NaOH
- 0.001mol will react with 0.002mol NaOH
Madd of NaOH
[tex]\\ \tt\hookrightarrow 0.002(40)=0.08g[/tex]
