sautterally sautterally
  • 18-02-2022
  • Mathematics
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Write the equation for a parabola with a focus at (7, -6) and a directrix at x = 5.
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stella8799
stella8799 stella8799
  • 18-02-2022

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palazzolorachel palazzolorachel
  • 18-02-2022

Answer:

[tex]x = \frac{1}{4} y^{2} +3y+15[/tex]

Step-by-step explanation:

Solution

As the focus is (7, -6), and

The directrix is x = 5,

so the parabola equation is

[tex](x-7)^{2}+[y-(-6)]^{2}=(x-5)^{2}[/tex]

[tex]x^{2}-14x+49+y^{2}+12y+36=x^{2} -10x+25[/tex]

[tex]4x=y^{2}+12y+60[/tex]

[tex]x=\frac{1}{4}y^{2}+3y+15[/tex]

{Points to focus distance and directrix are equal, to constitute a parabolic}

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