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If 3.50 mol of ethane, CzH6, undergo combustion according to the unbalaced equation given of oxygen requires ?


How many moles of each product formed?

If 350 mol of ethane CzH6 undergo combustion according to the unbalaced equation given of oxygen requires How many moles of each product formed class=

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brom2845

The Balance Chemical equation for said reaction is as follow,

                        C₂H₆   + 3.5 O₂    →    2 CO₂  +  3 H₂O

Or,

                       2 C₂H₆   + 7 O₂    →    4 CO₂  +  6 H₂O

According to equation,

       2 moles of Ethane react completely with  =  7 moles of Oxygen

So,

              4.20 moles of Ethane will react with  =  X moles of Oxygen

Solving for X,

                            X  =  (4.20 mol × 7 mol) ÷ 2 mol

                            X  = 14.7 moles of Oxygen

Result:

           14.7 moles of Oxygen are required to react with 4.20 moles of Ethane for complete reaction.

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