Answer:
O₂
Explanation:
2S(s) +3O₂(g) → 2SO₃(g)
The limiting reactant of a chemical reaction is one that we do not have enough of for the reaction to yield more products.
From the balanced equation above, the mole ratio of S to O₂ is 2 :3. This means that for every 2 moles of S, 3 moles of O₂ is needed.
Since we have 3.12 mol of S,
amount of O₂ needed
= (3.12 ÷2) ×3
= 4.68 mol
Since we only have 3.75 mol of O₂, O₂ is the limiting reactant.
