rayrayjune28 rayrayjune28
  • 19-11-2021
  • Mathematics
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8th-grade need help asap

8thgrade need help asap class=

Respuesta :

Bookworm58
Bookworm58 Bookworm58
  • 19-11-2021

Answer:

A. x ≤ -2

Hope this helps!

Answer Link
hnori22003
hnori22003 hnori22003
  • 19-11-2021

[tex] - 2(5x + 3) \geqslant 14[/tex]

Divide both sides by -2

[tex] \frac{ - 2(5x + 3)}{ - 2} \leqslant \frac{14}{ - 2} \\ [/tex]

[tex]5x + 3 \leqslant - 7[/tex]

Subtract both sides 3

[tex]5x + 3 - 3 \leqslant - 7 - 3[/tex]

[tex]5x \leqslant - 10[/tex]

Divide both sides by 5

[tex] \frac{5x}{5} \leqslant \frac{ - 10}{5} \\ [/tex]

[tex]x \leqslant - 2[/tex]

Answer Link

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