Answer:
A. [tex]h(x)=f(x+1)[/tex]
Step-by-step explanation:
Let's start doing exactly what each function says.
[tex]g(x) = 3x+3[/tex]
At this point, let's see what the various h-s do. Let's call each [tex]h_A... h_D[/tex] to understand which flavor of it we're talking about.
[tex]h_A(x)=f(x+1) = 3(x+1)=3x+3 = g(x)\\h_B(x)=2f(x)=2\cdot3x= 6x \ne g(x)\\h_C(x)=f(x-1)=3(x-1)=3x-3\ne g(x)\\h_D(x)= f(x)+1= 3x+1\ne g(x)[/tex]
