mallorypruitt10 mallorypruitt10
  • 18-11-2021
  • Mathematics
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3x + y + z = 6
3x - 2y + 2z = 14
3x + 3y - 3z = -6

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tshabalalanhlanhla29
tshabalalanhlanhla29 tshabalalanhlanhla29
  • 18-11-2021

Let's solve for x.

3x+y+z=6

Step 1: Add -y to both sides.

3x+y+z+−y=6+−y

3x+z=−y+6

Step 2: Add -z to both sides.

3x+z+−z=−y+6+−z

3x=−y−z+6

Step 3: Divide both sides by 3.

3x3

=−y−z+6/3

x=−1/3y+−1/3z+2

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