Respuesta :
1.
M(d) = x^2 - 9x - 10
R(d) = 2x + 10
A. Since M(d) and R(d) are technically the same term, we can substitute them for the other.
Substitute M(d) for R(d)’s expression
2x + 10 = x^2 - 9x - 10
x^2 - 11x - 20 = 0
Use this equation to put in the quadratic formula
x = (-(-11) +/- √((-11)^2 - 4(1)(-20)))/2(1)
x = (11 +/- √201)/2 or x = 12.5887… and -1.5887…
B. 12.6 days as there can’t be negative days
2.
Do the same substitution as the previous question
-t^2 - 2t + 36 = -2t + 20
Get all parts on the same side
t^2 - 16 = 0
Optional: quadratic formula
t = (-(0) +/- √((0)^2 - 4(1)(-16)))/2(1)
t = 4 and -4
b. -4 is not reasonable in this situation as time cannot be negative
c. 4 seconds
M(d) = x^2 - 9x - 10
R(d) = 2x + 10
A. Since M(d) and R(d) are technically the same term, we can substitute them for the other.
Substitute M(d) for R(d)’s expression
2x + 10 = x^2 - 9x - 10
x^2 - 11x - 20 = 0
Use this equation to put in the quadratic formula
x = (-(-11) +/- √((-11)^2 - 4(1)(-20)))/2(1)
x = (11 +/- √201)/2 or x = 12.5887… and -1.5887…
B. 12.6 days as there can’t be negative days
2.
Do the same substitution as the previous question
-t^2 - 2t + 36 = -2t + 20
Get all parts on the same side
t^2 - 16 = 0
Optional: quadratic formula
t = (-(0) +/- √((0)^2 - 4(1)(-16)))/2(1)
t = 4 and -4
b. -4 is not reasonable in this situation as time cannot be negative
c. 4 seconds