Answer:
There are none.
Step-by-step explanation:
No calculus involved:
The line, in slope-intercept form, has equation [tex]y=-10x+17[/tex], ie is always decreasing (easy to spot applying the definition)
Meanwhile, [tex]y=e^{5x}[/tex] is always increasing over its domain.
At no point the tangent will be decreasing.
Let's use calculus
We are to solve the equation [tex]y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2[/tex] which has no real solutions.
