Answer:
Well this is a function/ quadratic question.
So using this info we can make this into a standard form for quadratics which is
ax^2+bx+c=0
In this case c is 0 and we cna just make everything else equal to zero so.
-3x^2+6x=0
Now with this we can use the quadratic formula
-b±√(b²-4ac)/(2a)
So pluggin everything in
X=-6±√(6²-4(-3)0)/(2(-3))
Now we solve
36/-6
or -6
Now we just do
-6±-6
x= -12
x= 0
These are your answers
x=-12
x=0
