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Four different blocks are resting on the floor. They each have a different mass, and they are each made of a different material, so the coefficients of friction are not the same. Using the information in the table below, rank, from highest to lowest, the magnitude of the maximum horizontal force

Four different blocks are resting on the floor They each have a different mass and they are each made of a different material so the coefficients of friction ar class=

Respuesta :

To answer this question, it is necessary to apply the static condition from Newton´s Laws

The solution is:

Fd > Fc > Fa > Fb

From the body free diagram, and from the second Newton´s law of movement we get:

∑ Fx  = 0           F - Fr  = 0         F = Fr             Fr = μ×N

∑ Fy  = 0     N = m×g  ⇒   Therefore       Fr = μ×m×g

F = μ×m×g      g is the same in all the cases, then we just compare the products  μ×m

So when F is just greater than Fr, the body will start moving

we make a table, with values from the information table.

1.-  μ×m   =  0.5× 40  = 20

2.-μ×m   =  0.4× 80   = 16

3.- μ×m   = 0.7× 30   = 21

4.- μ×m   = 0.9× 35   = 31.5

According to the table, from highest to lowest the magnitude of the horizontal force is:

Fd > Fc > Fa > Fb

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