A. True
Explanation-
Let p(x) = x^3 – 7x^2 – 15x – 9
For checking that (x – 3) is a factor of p(x), we find : p(3)
p(3) = (3)^3 – 7(3)^2 + 15(3) – 9
= 27 – 63 + 45 – 9
= 72 – 72
= 0
Hence, (x – 3) is a factor of p(x).
By division of p(x) by x – 3, we get the quotient
= x^2 – 4x + 3
∴ x^3 – 7x^2 + 15x – 9
= (x – 3)(x^2 – 4x + 3)
= (x – 3)(x – 3)(x – 1)
= (x – 3)^2(x – 1)
