Respuesta :
N falls within the range of option B which is 700-949
- Let s be the original number of students and let c be the cost for each student initially.
The trophy costs $n. Thus;
sc = n - - - (eq 1)
- Now, 10 students left the school and each student had to pay an extra dollar to meet up with the cost of the trophy. Thus;
(s - 10)(c + 1) = n
sc - 10c + s - 10 = n - - - (eq 2)
- We are told that 15 students who did not play soccer should not contribute to the cost of the trophy which meant that students' cost increased by another $2 each. Thus;
(s - 10 - 15)(c + 1 + 2) = n
(s - 25)(c + 3) = n
sc - 25c + 3s - 75 = n - - - (eq 3)
- From eq 1, sc = n. Putting n for sc in eq 2 and 3 and simplifying, we have;
s - 10c = 10 - - - (eq 4)
3s - 25c = 75 - - - (eq 5)
- Multiply eq 4 by -3 and eq 5 by 1 and add them to get;
30c - 25c = -30 + 75
5c = 45
c = 45/5
c = $9
- Put 9 for c in s - 10c = 10 to get;
s - 10(9) = 10
s - 90 = 10
s = 10 + 90
s = 100
- Since n = sc
Thus; n = 100 × 9 = $900
Looking at the options, n falls in the range of option B which is 700-949
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