When the sum of twice a no. and 8 is at least 54 then the number will be "x = 23".
According to the question,
→ [tex]2x+8=54[/tex]
By subtracting "8" from both sides of the question, we get
→ [tex]2x+8-8=54-8[/tex]
→ [tex]2x=46[/tex]
→ [tex]x = \frac{46}{2}[/tex]
→ [tex]x = 23[/tex]
Thus the above solution is correct.
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