The first thing is to remember that [tex](f\circ g)(2) = f(g(2))[/tex] and you have to work from the inside. So first, from the table, we see
g(2) = 0
So this gives us [tex]f(\bold{g(2)}) =f(\bold{0})[/tex].
Now from the graph, f(0) = -3.
Putting that together, we have
[tex](f\circ g)(2) = -3[/tex]
