A ball is released at the top of a ramp at t = 0. Which is the speed of the ball at t = 4?
 
											 
											Answer:
For uniform acceleration
a = (v2 - v1) /t = 2.5 acceleration is constant 2.5
v2 = 2.5 * 4 v1 = 0 at t = 0
v2 = 2.5 m/s^2 * 4 s = 10 m/s