Respuesta :

[tex]\\ \sf\longmapsto Au^{5+}[/tex]

  • AU has atomic number 79 .
  • It donated 5electrons(5+) .
  • Hence it will has 79-5=74electrons

The EC will be

[tex]\\ \sf\longmapsto 1s^22s^22p^63s^23p^63d^{10}4s^24p^64d^{10}4f^{14}5s^25p^3[/tex]

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