Answer:
option a
Step-by-step explanation:
[tex] \sqrt{9 } = \sqrt{ {3}^{2} } = 3 \\ \sqrt{16 } = \sqrt{ {4}^{2} } = 4 \\ \sqrt{25} = \sqrt{ {5}^{2} } = 5 \\ \sqrt{36} = \sqrt{ {6}^{2} } = 6 \\ \sqrt{10} = \sqrt{2 \times 5} [/tex]
Hence, √10 is irrational number.
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