anahi92
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Magnesium occurs naturally in only three isotopes. ^24 Mg has an isotopic mass of 23.9850 amu and an abundance of 78.99%. ^25 Mg has an isotopic mass of 24.9858 amu and an abundance of 10.00%. Find the mass number of the last isotope of magnesium.

Can someone please explain how to solve this? *done mine the notes*

Magnesium occurs naturally in only three isotopes 24 Mg has an isotopic mass of 239850 amu and an abundance of 7899 25 Mg has an isotopic mass of 249858 amu and class=

Respuesta :

Answer:

25,98 amu and 11.01% abundance

Explanation:

1. Find the missing abundance

100 - 78.99 - 10 = 11.01 %

2. Using each mass and abundance and the periodic table for the Mg amu

And let Isotope = Mg

23.9850(78.99%) + 24.9858(10%) + Mg(11.01%) = 24.305 (100%)

Solve for Mg

Mg = 25,98

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