Answer:
[tex]\huge\boxed{\sf 9}[/tex]
Step-by-step explanation:
[tex]\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
Peace!
