lelammapukata03
lelammapukata03 lelammapukata03
  • 18-08-2021
  • Physics
contestada

please help me guys never mind the calculations ​

please help me guys never mind the calculations class=

Respuesta :

ghaithgh
ghaithgh ghaithgh
  • 18-08-2021

The shape is connected in parallel so;

5.1) Ans;

[tex] \frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{2} + \frac{1}{3} \\ \frac{1}{R} = \frac{3 + 2}{6} = \frac{5}{6} \\ R = \frac{6}{5} = 1.2 \: \: ohm[/tex]

5.2) Ans;

[tex] \frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \frac{1}{R} = \frac{1}{8} + \frac{1}{10} \\ \frac{1}{R} = \frac{5 + 4}{40} = \frac{9}{40} \\ R = \frac{40}{9} = 4.4 \: \: ohm[/tex]

I hope I helped you^_^

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