f(3)=8
Answer:
Solution given:
f(x)=ax^4-bx^2+x+5 and
f(-3)=2
f(-3)=a(-3)^4-b(-3)^2+(-3)+5
2=81a-9b-3+5
2=81a-9b+2
subtracting both side by 2 and adding 9b
2-2+9b=81a-9b+9b+2-2
9b=81a
now
f(3)=a(3)^(4)-b(3)^(2)+3+5
f(3)=81a-9b+8
substituting value of 81a
f(3)=9b-9b+8
f(3)=8
