Answer: The final value is 10
Step-by-step explanation:
We are given:
[tex]4\tan 45^o+(2\sin 45^o)(6\cos 45^o)[/tex]
We know that:
[tex]\tan 45^o=1\\\sin 45^o=\frac{1}{\sqrt{2}}\\\cos 45^o=\frac{1}{\sqrt{2}}[/tex]
Putting values in the given equation, we get:
[tex]\Rightarrow (4\times 1)+(2\times \frac{1}{\sqrt{2}})\times (6\times \frac{1}{\sqrt{2}})\\\\\Rightarrow 4+(\frac{2\times 6}{2})\\\\\Rightarrow (4+6)\\\\\Rightarrow 10[/tex]
Hence, the final value is 10
