Answer:
[tex]\sum\limits^3_{k=1}(k^3 - 6) = 18[/tex]
Step-by-step explanation:
Given
[tex]\sum\limits^3_{k=1}(k^3 - 6)[/tex]
Required
Evaluate
This means that we substitute 1 to 3 for k.
So, we have:
[tex]\sum\limits^3_{k=1}(k^3 - 6) = (1^3 - 6)+(2^3 - 6)+(3^3 - 6)[/tex]
[tex]\sum\limits^3_{k=1}(k^3 - 6) = (1 - 6)+(8 - 6)+(27 - 6)[/tex]
[tex]\sum\limits^3_{k=1}(k^3 - 6) = -5+2+21[/tex]
[tex]\sum\limits^3_{k=1}(k^3 - 6) = 18[/tex]
