Step-by-step explanation:
The given expression is :
[tex]\dfrac{a^3b^{-2}}{ab^{-4}}[/tex]
We need to simplify the above expression.
a³ is in numerator and a is in denominator. It gts cancelled.
[tex]\dfrac{a^3b^{-2}}{ab^{-4}}=\dfrac{a\times a\times a\times b\times b\times b\times b}{a\times b \times b}\\\\=\dfrac{a^2\times b^{-2}\times b^4}{1}\\\\=\dfrac{a^2}{b^{-2}}[/tex]
Hence, this is the required solution.
