Given:
The quadratic equation is:
[tex]x^2+x-30=0[/tex]
To find:
The solutions of the given equation.
Solution:
We have,
[tex]x^2+x-30=0[/tex]
Splitting the middle term, we get
[tex]x^2+6x-5x-30=0[/tex]
[tex]x(x+6)-5(x+6)=0[/tex]
[tex](x+6)(x-5)=0[/tex]
Using zero product property, we get
[tex]x+6=0[/tex] and [tex]x-5=0[/tex]
[tex]x=-6[/tex] and [tex]x=5[/tex]
Therefore, the solutions of the given quadratic equation are -6 and 5.
