Answer:
39.2 g
Explanation:
2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we convert 55.3 g of Ni₂O₃ into moles, using its molar mass:
55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we convert 0.334 Ni₂O₃ moles into Ni moles, using the stoichiometric coefficients of the balanced reaction:
0.334 mol Ni₂O₃ * [tex]\frac{4molNi}{2molNi_2O_3}[/tex] = 0.668 mol Ni
Finally we convert 0.668 Ni moles into grams, using its molar mass:
0.668 mol * 58.69 g/mol = 39.2 g
