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A triangle has the lengths of 16 and 4. What must the exact measurement of the hypotenuse be to make it a right triangle? Leave answer as a simplified radical.​

HELP PLEASE NO LINKSA triangle has the lengths of 16 and 4 What must the exact measurement of the hypotenuse be to make it a right triangle Leave answer as a si class=

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randaleechisholm

Answer:

4 [tex]\sqrt{17}[/tex]

Step-by-step explanation:

[tex]16^{2}[/tex] + [tex]4^{2}[/tex] = [tex]c^{2}[/tex]

256 + 16 = [tex]c^{2}[/tex]

[tex]\sqrt{272}[/tex] = c

[tex]\sqrt{16} \sqrt{17} = c[/tex]

4 [tex]\sqrt{17}[/tex] = c

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