Answer: [tex]-7\ \text{and}\ 5[/tex]
Step-by-step explanation:
Given
The equation is [tex]\left(x+1\right)^2-36=0[/tex]
Solving it
[tex]\Rightarrow \left(x+1\right)^2=36\\\\\Rightarrow \left(x+1\right)=\pm\sqrt{36}\\\\\Rightarrow x+1=\pm6\\\Rightarrow x=-7,5[/tex]
So, the lesser value of [tex]x[/tex] is [tex]-7[/tex] and the greater value is [tex]5[/tex].
