Respuesta :

ian2006huang

Answer:

a. Koby only

Step-by-step explanation:

KOBY

[tex]\frac{w^{3}*w^{5} }{ (w^{2} )^{4}} =\frac{w^{3+5} }{w^{2*4} } =\frac{w^{8}}{w^{8} } =1[/tex]

PAULO

[tex](m^{5} )^{2}*(m^{-3} )^{3}=m^{5*2} *m^{-3*3}=m^{10}*m^{-9}=m^{10-9}=m^1=m[/tex]
A. Koby only
Solution: w8/w8 =1

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