Respuesta :

tanmayakumarp3

Answer:

[tex] 2240 {m}^{2} [/tex]

Step-by-step explanation:

Given,

Parallel sides of the trapezium = 50m, 90m

Height of the trapezium = 32m

Therefore,

Area of the trapezium

[tex] = \frac{1}{2} \times sum \: of \: parallel \: sides \: \times \: height[/tex]

[tex] = \frac{1}{2} \times (50 + 90)m \times 32m[/tex]

= (50 + 90) m × 16m

= 140m × 16m

[tex] = 2240 {m}^{2} (ans)[/tex]

Answer:

A = 2240 m²

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = [tex]\frac{1}{2}[/tex]  h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 32 , b₁ = 90 and b₂ = 50 , then

A = [tex]\frac{1}{2}[/tex] × 32 × (90 + 50) = 16 × 140 = 2240 m²

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