Answer:
17.4 L
Explanation:
Step 1: Given data
- Moles of oxygen (n): 0.775 mol
- Pressure of the gas (P): 1 atm (standard pressure)
- Temperature of the gas (T): 273.15 K (standard temperature)
Step 2: Calculate the volume occupied by 0.775 moles of oxygen at standard temperature and pressure (STP)
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.775 mol × 22.4 L/1 mol = 17.4 L
