Answer:
9 - 166.42m²
10 - 308.8cm²
Step-by-step explanation:
The first figure shown is a triangular prism
We can find the surface area using this formula
[tex]SA=bh+L(S_1+S_2+h)[/tex]
where
B = base length
H = height
L = length
S1 = base length
S2 = slant height ( base's hypotenuse )
The triangular prism has the following dimensions
Base Length = 4m
Height = 5.7m
Length = 8.6m
S1 = 4m
S2 = 7m
Having found the needed dimensions we plug them into the formula
SA = ( 4 * 5.7 ) + 8.6 ( 4 + 7 + 5.7 )
4 * 5.7 = 22.8
4 + 7 + 5.7 = 16.7
8.6 * 16.7 = 143.62
22.8 + 143.62 = 166.42
Hence the surface area of the triangular prism is 166.42m²
The second figure shown is a pyramid
The surface area of a pyramid can be found using this formula
[tex]SA = A+\frac{1}{2} ps[/tex]
Where
A = Area of base
p = perimeter of base
s = slant height
The base of the pyramid is a square so we can easily find the area of the base by multiplying the base length by itself
So A = 8 * 8
8 * 8 = 64
So the area of the base (A) is equal to 64 cm^2
The perimeter of the base can easily be found by multiplying the base length by 4
So p = 4 * 8
4 * 8 = 32 so p = 32
The slant height is already given (15.3 cm)
Now that we have found everything needed we plug in the values into the formula
SA = 64 + 1/2 32 * 15.3
1/2 * 32 = 16
16 * 15.3 = 244.8
244.8 + 64 = 308.8
Hence the surface area of the pyramid is 308.8cm²
