Answer:
If you just solve normally, you will get x=2 and x=-3. But if you plug these in to check your work, you will find that they are wrong. Your answer is no solution
Step-by-step explanation:
ln(2x+3)+ln(x-2)=ln(x^2-2x)
Rule: log(a) + log(b) = log(a*b)
ln( (2x+3)(x-2) ) = ln(x^2-2x)
Rule: If log(a) = log(b) then a = b
(2x+3)(x-2) = x^2 - 2x
2x^2-x-6=x^2-2x
x^2+x-6=0
Using Quadratic Formula:
x = 2 and x = -3
But, plugging these numbers back into the original equation is false!
