Respuesta :

Answer: cage  I

Step-by-step explanation:

Given

43 gm of copper and 7 gram of other metal

Another cage has 83 gram of copper and 17 gm of other metals

Here, the percentage of copper is

For the first case

[tex]\Rightarrow \dfrac{43}{43+7}\times 100=86\%[/tex]

For the second case

[tex]\Rightarrow \dfrac{83}{83+17}\times 100=83\%[/tex]

So, the cage-I has more percentage of copper